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Answer :
The heat required to warm 1.70 kg of sand from 26.0 °C to 100.0 °C is 211,680,000 joules.
To calculate the heat required to warm a substance, we use the equation:
Q = mcΔT
Where:
Q = Heat energy (in joules)
m = Mass of the substance (in kilograms)
c = Specific heat capacity of the substance (in joules per kilogram per degree Celsius)
ΔT = Change in temperature (in degrees Celsius)
In this case, we need to calculate the heat required to warm 1.70 kg of sand from 26.0 °C to 100.0 °C.
First, we need to determine the specific heat capacity of sand. The specific heat capacity of sand can vary depending on its composition, but an average value is around 0.84 J/g°C or 840 J/kg°C.
Converting the mass of sand to grams:
Mass of sand = 1.70 kg × 1000 g/kg = 1700 g
Now we can calculate the heat required:
Q = mcΔT
Q = (1700 g) × (840 J/kg°C) × (100.0°C - 26.0°C)
Q = (1700 g) × (840 J/kg°C) × (74.0°C)
Note that the grams in the mass cancel out, leaving us with the heat energy in joules.
Calculating the heat required:
Q = 1700 g × 840 J/kg°C × 74.0°C
Q = 211,680,000 J
Therefore, the heat required to warm 1.70 kg of sand from 26.0 °C to 100.0 °C is 211,680,000 joules.
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