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A projectile is shot from a cannon at a 40° angle relative to the ground. If the projectile started with a vertical speed of 35.9 m/s, what range did the object move, assuming the projectile comes back down to the ground?

Please make a drawing to help understand better. Thank you.

Answer :

Final answer:

The range of the projectile is the horizontal distance it travels before hitting the ground. To calculate the range, we can use the formula Range = (Initial velocity^2 * sin(2 * launch angle)) / acceleration due to gravity. For the given values of an initial velocity of 35.9 m/s and a launch angle of 40 degrees, the range can be calculated using this formula.

Explanation:

To calculate the range of the projectile, we can use the following formula:

Range = (Initial velocity^2 * sin(2 * launch angle)) / acceleration due to gravity

Given that the initial velocity is 35.9 m/s and the launch angle is 40 degrees, we can substitute these values into the formula:

Range = (35.9^2 * sin(2 * 40)) / 9.8

Calculating this expression gives us the range of the projectile.

Now, let's make a drawing to better understand the situation:

Learn more about projectile motion here:

https://brainly.com/question/12860905

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