A rifle is mounted in a holding apparatus and adjusted to fire horizontally at a target 125.0 m away. The muzzle velocity of the rifle is 1,895 m/s. If the center of the target is at the same height as the barrel of the rifle, how far below the center does the bullet hit the target?

Question

24-10-2023
Physics

High School

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A rifle is mounted in a holding apparatus and adjusted to fire horizontally at a target 125.0 m away. The muzzle velocity of the rifle is 1,895 m/s. If the center of the target is at the same height as the barrel of the rifle, how far below the center does the bullet hit the target?

Answer :

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lalithase81 lalithase81 · Answer 1 · 2025-01-13T04:20:03-05:00

Final answer:

The bullet fired from the rifle, moving at a heavy velocity of 1895 m/s towards a target 125 m away, still falls under the influence of gravity. The time it spends in flight is used to calculate the vertical distance fallen due to gravity, which is approximated to be 2.2 cm.

Explanation:

This question involves the concept of projectile motion. When the rifle fires, the bullet is subjected to the downward acceleration due to gravity (9.81 m/s^2) while moving horizontally at a constant velocity.

Although the bullet travels horizontally at high velocity, it's still subject to the pull of gravity. Let's calculate the time the bullet spends in flight, which is the distance to the target divided by the horizontal velocity.

So, time of flight: t = 125.0 m /1895 m/s ≈ 0.066 seconds.

Now, let's use this time to find the vertical height fallen:

Vertical distance fallen: h = 0.5*g*t^2, where 'g' stands for acceleration due to gravity.

So, h = 0.5*9.81 m/s^2*(0.066s)^2 ≈ 0.022 m or 2.2 cm

Therefore, the bullet would hit 2.2 cm below the center of the target.

Learn more about Projectile Motion here:

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