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Assuming the inter-green time is 12 seconds, the red/amber time is 2 seconds, and the yellow time is 4 seconds, the all-red time will be:

A. 16 seconds
B. 6 seconds
C. 3 seconds
D. 8 seconds

The saturation flow rate if saturation headways are 2 seconds is:

A. 1000 veh/hr
B. 3600 veh/hr
C. 1800 veh/hr
D. 7200 veh/hr

Answer :

Final answer:

The all-red time in a traffic signal system, assuming the given inter-green time is 12 sec, the red/amber is 2 sec, and the yellow time is 4 sec, would be 6 seconds.

Explanation:

In a traffic signal system, the all-red time refers to the period when all signal lights are red and no vehicles are allowed to move in any direction. It is an essential part of the signal cycle and is designed to ensure a safe transition between different phases.

The given information states that the inter-green time is 12 seconds, the red/amber time is 2 seconds, and the yellow time is 4 seconds. To calculate the all-red time, we need to consider the time required for each phase.

First, we add the red/amber time and the yellow time to get the total time for the clearance phase: 2 seconds + 4 seconds = 6 seconds.

Next, we subtract the clearance phase time from the inter-green time to get the all-red time: 12 seconds - 6 seconds = 6 seconds.

Therefore, the all-red time in this scenario is 6 seconds.

Learn more about calculating the all-red time in a traffic signal system here:

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