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If 36.6 g of CH₃OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of CH₃OH in the resulting solution?

Answer :

In chemistry, concentration alludes to how much a substance is in a characterized space. The concentration of CH₃OH in the resulting solution is 2.284 M.

The concentration of a solution is a proportion of how much solute that has been disintegrated in a given measure of dissolvable or arrangement. A concentrated arrangement is one that has a moderately huge measure of broken-down solute. A weakened arrangement is one that has a moderately limited quantity of broken-up solute. To calculate the concentration of CH₃OH in the resulting solution, we need to know the number of moles of CH₃OH present in the 500.0 mL solution:

Calculate the number of moles of CH₃OH:

moles = mass / molar mass

moles = 36.6 g / 32.04 g/mol

moles = 1.142 mol

Calculate the concentration of CH₃OH:

concentration = moles / volume

concentration = 1.142 mol / 0.500 L

concentration = 2.284 M

Therefore, the concentration of CH₃OH in the resulting solution is 2.284 M.

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