Thank you for visiting A four bend saddle has been fabricated in a length of 1 2 inch RMC to go over an obstruction Based on the photo provided. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
To layout a four-bend saddle in an RMC, measurements of the obstruction's height and application of the shrinkage factor for 22.5° bends are necessary, alongside allowances for connections to a junction box.
Explanation:
The question concerns a four-bend saddle fabrication using a 1/2-inch Rigid Metal Conduit (RMC) to pass over an obstruction. The student is tasked to determine the distance between bend centers using 22.5° bends and make allowances for the connection of the conduit to a junction box using locknuts.
To calculate this distance, we would typically use the formula for the shrinkage per inch of conduit, which changes depending on the angle of the bend. For a 22.5° bend, the shrinkage is usually 3/16 inch per inch of offset.
However, without a photo or additional information, such as the height of the obstacle to be cleared, exact calculations cannot be made, and specific values would be needed to provide a precise answer.
For the given scenario, to determine the distance between bend centers, we would follow these steps:
- Measure the height of the obstruction.
- Calculate the total amount of shrinkage using the shrinkage factor for the bend angle.
- Use the shrinkage and height to determine the distances between bends.
- Remember to allow extra length for the connection to a junction box.
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Rewritten by : Jeany
