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The heat of vaporization of octane is 39.4 kJ/mol, and the entropy of vaporization is 99.0 J/(mol·K). What is the boiling point of octane?

Answer :

Final answer:

The boiling point of a substance can be estimated using the Clausius-Clapeyron equation, which relates the vapor pressure, enthalpy of vaporization, and temperature.

Explanation:

The boiling point of a substance is the temperature at which it changes from a liquid to a gas at a given pressure. The enthalpy of vaporization and the entropy of vaporization are two important properties that can provide information about the boiling point of a substance.

To estimate the boiling point of octane, we can use the Clausius-Clapeyron equation, which relates the vapor pressure, enthalpy of vaporization, and temperature. The equation is:

ln(P2/P1) = -ΔHvap/R * (1/T2 - 1/T1)

In this equation, P1 and T1 are the values at which the vapor pressure and temperature are known, and P2 and T2 are the values at which we want to find the vapor pressure and temperature.

Using the given values, we can calculate the boiling point of octane.

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