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An AC voltage with a peak value of 180 V is applied across a 330 Ω resistor.

What are the RMS and peak currents in the resistor?

Answer :

To find the RMS and peak currents in the resistor, we use Ohm's Law and the definitions of RMS and peak values. Given a peak voltage of 180 V and resistance of 330 Ω, we find the RMS current to be approximately 0.385 A and the peak current to be approximately 0.545 A.

To find the RMS and peak currents in the resistor, we can use Ohm's Law and the definitions of RMS and peak values.

Ohm's Law states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R).

Here, peak voltage (Vp) = 180 V
Resistance (R) = 330 Ω

To find the RMS current (Irms), we need to convert the peak voltage to RMS voltage first.

The RMS voltage (Vrms) is equal to the peak voltage divided by the square root of 2.
Vrms = Vp / √2
Vrms = 180 V / √2
Vrms ≈ 127.28 V

Now that we have the RMS voltage, we can find the RMS current using Ohm's Law.
Irms = Vrms / R
Irms = 127.28 V / 330 Ω
Irms ≈ 0.385 A

Therefore, the rms current in the resistor is approximately 0.385 A.

To find the peak current (Ip), we can use the peak voltage and the resistance.
Ip = Vp / R
Ip = 180 V / 330 Ω
Ip ≈ 0.545 A

Therefore, the peak current in the resistor is approximately 0.545 A.

In summary, the RMS current in the resistor is approximately 0.385 A. The peak current in the resistor is approximately 0.545 A.

In conclusion, the RMS current represents the effective or root-mean-square value of the current, and it is found to be approximately 0.385 A. The peak current, which represents the maximum instantaneous value of the current, is found to be approximately 0.545 A. These calculations are based on the given peak voltage of 180 V and a resistor with a resistance of 330 Ω, using Ohm's Law and the conversion between peak and RMS values.

To know more about Ohm's Law:

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