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How to do this problem?
They are asking for the probability of
a.) Tea or cookies
b.) Coffee, given that it contains mugs
c.) Coffee and Candy

How to do this problem They are asking for the probability of a Tea or cookies b Coffee given that it contains mugs c Coffee

Answer :

By choosing 1 basket at random, the probability that it contains;

a.) Tea or cookies is 0.8554.

b.) Coffee, given that it contains mugs is 0.4815.

c.) Coffee and candy is 0.1687.

Part a.

First of all, we would organize the data into a table for better understanding as follows:

Cookies Mugs Candy Total

Coffee 12 13 14 39

Tea 15 14 15 44

Total 27 27 29 83

For the probability that a gift basket contains either tea or cookies, we add the total number of tea baskets to the total number of cookies, and then divide by the total number of baskets;

P(Tea or cookies) = (44 + 27)/83

P(Tea or cookies) = 0.8554.

Part b.

For the conditional probability of a basket containing coffee, given that it already contains mugs, we would divide the number of coffee baskets that contain mugs by the total number of baskets that contain mugs;

P (Coffee | mugs) = (Coffee and mugs))/mugs

P (Coffee | mugs) = 13/27

P (Coffee | mugs) = 0.4815.

Part c.

For the probability that a basket contains both coffee and candies, we would divide the number of coffee baskets that contain candies by the total number of baskets;

P(Coffee and candies) = (Coffee and candies)/Total baskets

P(Coffee and candies) = 14/83

P(Coffee and candies) = 0.1687.

Complete Question;

The Gift Basket Store had the following premade gift baskets containing the following combinations in stock.

Cookies Mugs Candy

Coffee 12 13 14

Tea 15 14 15

Choose 1 basket at random. Find the probability that it contains

a.) Tea or cookies

b.) Coffee, given that it contains mugs

c.) Coffee and Candy

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Rewritten by : Jeany

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