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Answer :
Answer:
0.08°
Explanation:
velocity of projection, u = 420 m/s
Horizontal range, R = 49.8 m
Let the angle of projection is θ.
Use the formula for the horizontal range.
[tex]R=\frac{u^{2}Sin2\theta }{g}[/tex]
[tex]49.8=\frac{420^{2}Sin2\theta }{9.8}[/tex]
Sin 2θ = .0027
2θ = 0.1585
θ = 0.08°
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