Thank you for visiting A given compound has the following composition 20 3 g mercury and 1 70 g oxygen Find the empirical formula. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To find the empirical formula of the compound, you need to find the ratio of the elements present in the smallest whole numbers. You can do this by dividing each element's mass by its atomic mass and then dividing the result by the smallest ratio found.
For example:
Mercury (Hg) atomic mass = 200.59 g/mol
Oxygen (O) atomic mass = 15.999 g/mol
Hg mass = 20.3 g / 200.59 g/mol = 0.101 mol
O mass = 1.70 g / 15.999 g/mol = 0.106 mol
Dividing the two mole ratios by the smaller ratio (0.106), we get:
Hg = 0.101 / 0.106 = 0.95 (rounded to 1)
O = 0.106 / 0.106 = 1.0
So, the empirical formula of the compound is HgO.
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