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A gas held at 3.2 atm and 250 K takes up a volume of 4.0 L. The gas has a mass of 99.8 g. What is the identity of the gas? (R = 0.0821 L·atm/K·mol)

A. Fluorine
B. Chlorine
C. Bromine
D. None of the above

Answer :

Final answer:

To determine the identity of the gas, we can use the ideal gas law formula PV = nRT. By rearranging the formula and plugging in the given values, we find that the number of moles of gas is approximately 0.212 moles. Comparing the molar masses of the given gases, we can conclude that none of them match the calculated molar mass of the gas. Therefore, the correct answer is D) None of the above.

Explanation:

To determine the identity of the gas, we can use the ideal gas law formula:

PV = nRT

Where:

  • P is the pressure in atmospheres (3.2 atm)
  • V is the volume in liters (4.0 L)
  • n is the number of moles of gas, which we can find using the mass of the gas
  • R is the ideal gas constant (0.0821 L·atm/K·mol)
  • T is the temperature in Kelvin (250 K)

Rearranging the formula to solve for n, we get:

n = PV / RT

Plugging in the given values, we have:

n = (3.2 atm)(4.0 L) / (0.0821 L·atm/K·mol)(250 K)

Solving this equation, we find that n is approximately 0.212 moles. Comparing the molar masses of the given gases (He: 4 g/mol, NH3: 17 g/mol, O2: 32 g/mol), we can see that none of them match the molar mass calculated for the gas in question. Therefore, the correct answer is D) None of the above.

Learn more about determining the identity of a gas here:

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