Answer :

The amount of heat required to warm 1.70 kg of sand from 24.0 °C to 100.0 °C is approximately 108,192 joules.

To calculate the amount of heat required to warm a substance, we can use the equation:
Q = mcΔT

Where:
Q = heat energy (in joules)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in joules per kilogram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)

In this case, we have 1.70 kg of sand and we want to warm it from 24.0 °C to 100.0 °C.

First, we need to find the specific heat capacity of sand. The specific heat capacity of sand is typically around 0.84 joules per gram per degree Celsius. We need to convert the mass of the sand from kilograms to grams, so:

Mass of sand = 1.70 kg × 1000 g/kg = 1700 g
Now we can calculate the amount of heat required using the equation:
Q = mcΔT
Q = (1700 g) × (0.84 J/g°C) × (100.0 °C - 24.0 °C)

Note: The specific heat capacity of sand can vary slightly depending on its composition, so this is an approximate value.
Calculating the value gives us:
Q = 1700 g × 0.84 J/g°C × 76.0 °C
Q = 108,192 J

To know more about heat, refer here:

https://brainly.com/question/30603212#

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Rewritten by : Jeany

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