High School

Thank you for visiting What is the final temperature when 625 grams of water at 75 0 C loses tex 7 96 times 10 4 text J tex. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

What is the final temperature when 625 grams of water at 75.0°C loses [tex]$7.96 \times 10^4 \, \text{J}$[/tex]?

Answer :

Final answer:

The final temperature of the water, after losing 7.96 x 10⁴ J, is 44.7°C. This is calculated by using the formula for heat loss q = mcΔT and finding the change in temperature, which is then subtracted from the initial temperature.

Explanation:

To find the final temperature of the water, we need to first understand that the heat loss of water is determined by the formula: q = mcΔT, where 'q' is the heat energy in Joules, 'm' is the mass in grams, 'c' is the specific heat capacity of the substance (for water, it's 4.18 J/g°C), and 'ΔT' is the change in temperature. In this case, we know that q = -7.96 x 10⁴ J (the heat lost, hence the negative sign), m = 625 g, and c = 4.18 J/g°C.

We can rearrange the formula to solve for 'ΔT': ΔT = q / (mc). When we plug in the values we get ΔT = -7.96 x 10⁴ J / (625 g * 4.18 J/g°C) = -30.3°C.

To find the final temperature, we subtract this value from the initial temperature: 75.0°C - 30.3°C = 44.7°C. So, the final temperature of the water is 44.7°C.

Learn more about Heat Loss Calculation here:

https://brainly.com/question/33903861

#SPJ11

Thank you for reading the article What is the final temperature when 625 grams of water at 75 0 C loses tex 7 96 times 10 4 text J tex. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany

Other Questions