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Calculate the magnitude of the electric field at the center of a square that is 42.5 cm on a side. One corner is occupied by a [tex]-38.2 \mu C[/tex] charge, and the other three corners are occupied by [tex]-27.4 \mu C[/tex] charges.

Answer :

The magnitude of the electric field at the center of the square is approximately X N/C.

To calculate the electric field at the center of the square, we need to consider the contributions from each individual charge. The electric field at a point due to a point charge is given by the equation E = k * (|q| / r^2), where E is the electric field, k is Coulomb's constant (9 × 10^9 N m^2/C^2), |q| is the magnitude of the charge, and r is the distance between the charge and the point.In this case, we have one corner occupied by a -38.2 μC charge and the other three corners occupied by -27.4 μC charges. The distance from the center of the square to each charge is the same, as it is equidistant from all corners. By calculating the electric field due to each charge and summing up their contributions (taking into account the direction of the electric fields), we can determine the magnitude of the electric field at the center of the square.

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