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Answer :
Final answer:
a) The electric field at the surface of the spherical shell is 1.49 x 10^8 N/C. b) The potential difference between the center and the surface of the shell is 1.79 x 10^9 V.
Explanation:
a) To calculate the electric field at the surface of the spherical shell, we can use the formula E = k(Q/r^2), where k is the electrostatic constant, Q is the charge on the shell, and r is the radius of the shell. Plugging in the values, E = (9 x 10^9 Nm^2/C^2)(7.25C)/(0.366m)^2 = 1.49 x 10^8 N/C.
b) To calculate the potential difference between the center and the surface of the shell, we can use the formula V = k(Q/r), where V is the potential difference, Q is the charge on the shell, and r is the radius of the shell. Plugging in the values, V = (9 x 10^9 Nm^2/C^2)(7.25C)/(0.366m) = 1.79 x 10^9 V.
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