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1. A car accelerates from 0 to 35.0 miles per hour in 4.75 seconds. Calculate the acceleration of the car and express your answer in meters per second squared.



Note: 1 mile = 1609 meters and 1 hour = 3600 seconds.

Answer :

We start with the information that the car goes from an initial speed of $u=0$ to a final speed of $35.0\ \text{mph}$ in a time interval of $t=4.75\ \text{s}$. Our goal is to express the acceleration in meters per second squared.

**Step 1. Convert the final speed from miles per hour to meters per second.**

We use the conversion factors:
- $1\ \text{mile} = 1609\ \text{meters}$,
- $1\ \text{hour} = 3600\ \text{seconds}$.

Thus, the conversion factor from miles per hour to meters per second is
$$
\frac{1609\ \text{meters}}{3600\ \text{seconds}} \approx 0.4469444444.
$$

The final speed in meters per second is then calculated as
$$
v = 35.0\ \text{mph} \times 0.4469444444\ \frac{\text{m/s}}{\text{mph}} \approx 15.64305556\ \text{m/s}.
$$

**Step 2. Calculate the acceleration.**

Since the car starts from rest ($u = 0$), the acceleration $a$ can be found using the formula
$$
a = \frac{v - u}{t}.
$$

Substituting the known values:
$$
a = \frac{15.64305556\ \text{m/s} - 0\ \text{m/s}}{4.75\ \text{s}} \approx 3.2932748538\ \text{m/s}^2.
$$

**Step 3. State the final answer.**

Therefore, the acceleration of the car is approximately
$$
3.293\ \text{m/s}^2.
$$

This is the acceleration expressed in meters per second squared.

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Rewritten by : Jeany