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Answer :
Sure! Let's solve the problem of determining how many grams of CO₂ are produced by the combustion of 38.2 liters of C₂H₆ gas.
Step 1: Calculate the moles of C₂H₆.
We are given the volume of C₂H₆ as 38.2 liters. According to the ideal gas law, at standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, we can calculate the moles of C₂H₆ gas as:
[tex]\[ \text{Moles of C}_2\text{H}_6 = \frac{38.2 \text{ liters}}{22.4 \text{ liters/mole}} \][/tex]
Step 2: Determine the moles of COâ‚‚ produced.
From the balanced chemical equation for the combustion of ethane ([tex]\( \text{C}_2\text{H}_6 \)[/tex]):
[tex]\[ 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} \][/tex]
We see that 2 moles of C₂H₆ produce 4 moles of CO₂. Hence, for each mole of C₂H₆, 2 moles of CO₂ are produced. So, we multiply the moles of C₂H₆ by 2 to get the moles of CO₂:
[tex]\[ \text{Moles of CO}_2 = \text{Moles of C}_2\text{H}_6 \times 2 \][/tex]
Step 3: Convert moles of COâ‚‚ to grams.
The molar mass of COâ‚‚ is 44.01 grams/mole. We'll use this to convert the moles of COâ‚‚ to grams:
[tex]\[ \text{Mass of CO}_2 = \text{Moles of CO}_2 \times 44.01 \text{ g/mole} \][/tex]
Final Calculation:
Calculating all these, you will find approximately 150 grams of COâ‚‚ are produced.
Therefore, the correct answer is 150 g COâ‚‚.
Step 1: Calculate the moles of C₂H₆.
We are given the volume of C₂H₆ as 38.2 liters. According to the ideal gas law, at standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, we can calculate the moles of C₂H₆ gas as:
[tex]\[ \text{Moles of C}_2\text{H}_6 = \frac{38.2 \text{ liters}}{22.4 \text{ liters/mole}} \][/tex]
Step 2: Determine the moles of COâ‚‚ produced.
From the balanced chemical equation for the combustion of ethane ([tex]\( \text{C}_2\text{H}_6 \)[/tex]):
[tex]\[ 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} \][/tex]
We see that 2 moles of C₂H₆ produce 4 moles of CO₂. Hence, for each mole of C₂H₆, 2 moles of CO₂ are produced. So, we multiply the moles of C₂H₆ by 2 to get the moles of CO₂:
[tex]\[ \text{Moles of CO}_2 = \text{Moles of C}_2\text{H}_6 \times 2 \][/tex]
Step 3: Convert moles of COâ‚‚ to grams.
The molar mass of COâ‚‚ is 44.01 grams/mole. We'll use this to convert the moles of COâ‚‚ to grams:
[tex]\[ \text{Mass of CO}_2 = \text{Moles of CO}_2 \times 44.01 \text{ g/mole} \][/tex]
Final Calculation:
Calculating all these, you will find approximately 150 grams of COâ‚‚ are produced.
Therefore, the correct answer is 150 g COâ‚‚.
Thank you for reading the article How many grams of tex CO 2 tex will be produced by the combustion of 38 2 liters of tex C 2H 6 tex gas. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
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