Thank you for visiting For an unconfined aquifer observed using two wells the hydraulic conductivity is tex 4 85 text km yr tex The elevation reading at Station A. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The flow through a section of 800 meters in length in the unconfined aquifer is approximately 4,232 cubic meters per year.
Explanation:
To determine the flow through a section of 800 meters in length in an unconfined aquifer, we can use Darcy's law:
Q = K * A * (h1 - h2) / L
Where:
- Q is the flow rate
- K is the hydraulic conductivity
- A is the cross-sectional area
- h1 and h2 are the hydraulic heads at Station A and Station B, respectively
- L is the distance between Station A and Station B
First, let's calculate the hydraulic gradient:
h1 - h2 = 97.8 - 92.8 = 5 meters
Next, let's calculate the cross-sectional area:
A = average depth * length = 23.00 * 800 = 18,400 square meters
Now, we can calculate the flow rate:
Q = 4.85 km/yr * 18,400 square meters * 5 meters / 100 meters = 4.85 * 18,400 * 5 / 100 = 4,232 cubic meters per year
Therefore, the flow through a section of 800 meters in length in the unconfined aquifer is approximately 4,232 cubic meters per year.
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