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A gas occupies a volume of 35.9 mL at a temperature of 22.0°C. What volume will the same gas occupy at a temperature of 28.0°C?

Answer :

The volume of the gas after an increase in temperature to 28.0 C is 45.69 ml

Given Data

  • V1 = 35.9ml
  • T1 = 22.0 Degrees
  • T2 = 28.0 Degrees

We know that the expression relating volume and temperature is given as

V1/T1 = V2/T2

Substituting our given data into the expression above we have

35.9/22.0 = V2/28.0

Making V2 the subject of the formula we have

V2 = 35.9*28.0/22/0

V2 = 1005.2/22.0

V2 = 45.69 ml

Learn more about temperature-volume relationship here:

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