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Answer :
To solve this problem, follow these steps:
1. We are given that the atomic mass of potassium is [tex]$39.1 \, \text{g/mol}$[/tex]. This means that one mole of potassium has a mass of [tex]$39.1 \, \text{g}$[/tex].
2. One mole is defined as having exactly [tex]$6.02 \times 10^{23}$[/tex] atoms. Since the problem gives us [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium, we have exactly one mole of potassium.
3. To find the mass of one mole of potassium, we simply use the atomic mass:
[tex]$$
\text{Mass} = 1 \, \text{mole} \times 39.1 \, \text{g/mol} = 39.1 \, \text{g}.
$$[/tex]
Thus, the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium is [tex]$39.1 \, \text{g}$[/tex], which corresponds to option B.
1. We are given that the atomic mass of potassium is [tex]$39.1 \, \text{g/mol}$[/tex]. This means that one mole of potassium has a mass of [tex]$39.1 \, \text{g}$[/tex].
2. One mole is defined as having exactly [tex]$6.02 \times 10^{23}$[/tex] atoms. Since the problem gives us [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium, we have exactly one mole of potassium.
3. To find the mass of one mole of potassium, we simply use the atomic mass:
[tex]$$
\text{Mass} = 1 \, \text{mole} \times 39.1 \, \text{g/mol} = 39.1 \, \text{g}.
$$[/tex]
Thus, the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium is [tex]$39.1 \, \text{g}$[/tex], which corresponds to option B.
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