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Thank you for visiting Given that the specific heat of chromium is 0 455 J g∠K find the final temperature after 35 9 J of energy is removed. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

Given that the specific heat of chromium is 0.455 J/g∙K, find the final temperature after 35.9 J of energy is removed from 11.7 g of chromium initially at 28.5°C.

Answer :

Final answer:

The final temperature of the chromium after removing energy can be calculated using the specific heat equation. Plugging in the given values and solving for ∆T, the change in temperature, we find it to be -7.847K. Adding this change to the initial temperature of 28.5°C, we get a final temperature of 20.653°C.

Explanation:

The final temperature can be calculated using the specific heat formula:

Q = m * c * ∆T

Where:

Q is the energy transferred (given as -35.9J in this case)

m is the mass of the material (11.7g)

c is the specific heat capacity (0.455J/g∙K)

∆T is the change in temperature (to be calculated)

Plugging in the values and solving for ∆T:

(-35.9J) = (11.7g) * (0.455J/g∙K) * ∆T

∆T = (-35.9J) / (11.7g * 0.455J/g∙K)

∆T = -7.847K

Finally, to find the final temperature:

Final temperature = Initial temperature + ∆T = 28.5°C + (-7.847K) = 20.653°C

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Rewritten by : Jeany

Answer:

[tex]T_2=35.2\°C[/tex]

Explanation:

Hello,

In this case, since the heat is computed in terms of mass, specific heat and temperature as follows:

[tex]Q=mCp(T_2-T_1)[/tex]

In such a way, for the given heat, we obtain the following temperature:

[tex]T_2=T_1+\frac{Q}{mCp}\\ \\T_2=28.5\°C+\frac{35.9J}{11.7g*0.455\frac{J}{g\°C} }\\ \\T_2=35.2\°C[/tex]

Best regards.