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Answer :
Final answer:
This is a physics question about projectile motion. Given the horizontal distance to the target and the drop height, we find the time it takes for the bullet to hit the target and derive the initial speed.
Explanation:
The subject of this question is Physics, and it is a problem involving the concept of projectile motion. When a rifle fires a bullet horizontally, due to the force of gravity, the bullet begins to drop below the line of sight as soon as it leaves the barrel. Even travelling at a high velocity, it cannot avoid this downward acceleration.
First we need to find the time it takes for the bullet to hit the target. We can calculate this using the equation of motion, s = ut + 1/2gt², where s is the displacement (2.5 cm = 0.025 m), u is the initial vertical speed (0, because the bullet is fired horizontally), g is the acceleration due to gravity (9.81 m/s²), and t is the time.
Solving for t gives us the time it takes for the bullet to fall 2.5 cm. Since the horizontal travel time and vertical drop time are the same, this is also the time it takes for the bullet to hit the target. The initial speed of the bullet is then just the horizontal distance to the target (51 m) divided by this time.
Learn more about Projectile Motion here:
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