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Answer :
This is the frequency distribution table for the given data set with a class width of 0.5 and a starting value of 97.0 degrees.
To construct a frequency distribution table for the given data set with a class width of 0.5 and a starting value of 97.0 degrees, we can follow these steps:
1. Determine the number of classes:
To determine the number of classes, we calculate the range of the data by subtracting the smallest value from the largest value:
Range = 99.4 - 97.0 = 2.4
We can choose the number of classes as the range divided by the class width (0.5) and round it up to the nearest whole number:
Number of classes = ceil(Range / Class width) = ceil(2.4 / 0.5) = ceil(4.8) = 5
2. Determine the class intervals:
Starting with the given starting value (97.0 degrees), we can create class intervals by adding the class width repeatedly:
Class intervals: 97.0 - 97.5, 97.5 - 98.0, 98.0 - 98.5, 98.5 - 99.0, 99.0 - 99.5, 99.5 - 100.0
3. Count the frequency of each class:
Count how many data points fall into each class interval.
- For the first class interval (97.0 - 97.5), we have:
Frequency: 2 (97.1, 97.2)
- For the second class interval (97.5 - 98.0), we have:
Frequency: 4 (97.5, 97.6, 97.6, 97.8)
- For the third class interval (98.0 - 98.5), we have:
Frequency: 4 (98.0, 98.0, 98.2, 98.2)
For the fourth class interval (98.5 - 99.0), we have:
Frequency: 5 (98.2, 98.3, 98.4, 98.6, 98.6)
- For the fifth class interval (99.0 - 99.5), we have:
Frequency: 4 (98.7, 98.7, 98.9, 99.1)
- For the last class interval (99.5 - 100.0), we have:
Frequency: 1 (99.4)
4. Create the frequency distribution table:
Combine the class intervals and their corresponding frequencies into a table format.
Class Interval | Frequency
-----------------|----------
97.0 - 97.5 | 2
97.5 - 98.0 | 4
98.0 - 98.5 | 4
98.5 - 99.0 | 5
99.0 - 99.5 | 4
99.5 - 100.0 | 1
This is the frequency distribution table for the given data set with a class width of 0.5 and a starting value of 97.0 degrees.
Learn more about Class Interval here:
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Rewritten by : Jeany
