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Let's combine our rock tossing with horizontal motion. This kind of problem can be handled by considering the vertical and horizontal motions separately. The horizontal velocity is constant (we ignore air resistance).

Recall from your study of trigonometry that if you release a rock at a speed in a direction that makes an angle with the horizontal, then the initial vertical velocity and the horizontal velocity are given by:

You shoot a rifle at an angle of 27 degrees. The bullet leaves your rifle at a height of 6 feet and a speed of 894 feet per second. It hits the ground after a certain number of seconds at a distance of a certain number of feet.

Note: Again, ignore air resistance. When shooting a rifle, this is, of course, a gross simplification. Even so, that's some rifle!

Answer :

The range of the bullet is = 4.43 miles.

The vertical and horizontal velocity of the bullet can be found using the following equations:

v_x = v * cos(θ)

v_y = v * sin(θ)

Where v is the initial speed, and θ is the angle of release with the horizontal. In this case, v = 894 feet per second, and θ = 27 degrees.

So, the horizontal velocity is:

v_x = 894 * cos(27) = 813.07 feet per second

And the vertical velocity is:

v_y = 894 * sin(27) = 463.6 feet per second

Next, we can use the equations of motion to find the time of flight and the range of the bullet.

The time of flight can be found using the equation:

t = 2 * v_y / g

Where g is the acceleration due to gravity (g = 32.2 feet per second^2).

So, the time of the flight is:

t = 2 * 463.6 / 32.2 = 28.77 seconds

The range of the bullet can be found using the equation:

x = v_x * t

So, the range of the bullet is:

x = 813.07 * 28.77 = 23449.05 feet = 4.43 miles.

Learn more about vertical and horizontal velocity here:https://brainly.com/question/24949996

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Rewritten by : Jeany

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