College

Thank you for visiting What is the empirical formula of a compound that contains 10 0 g aluminum and 39 4 g chlorine Select the correct answer below A. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

What is the empirical formula of a compound that contains 10.0 g aluminum and 39.4 g chlorine?

Select the correct answer below:

A. AlClâ‚‚
B. AlCl
C. AlCl
D. AlCl

Answer :

Final answer:

The empirical formula of the compound is AlCl3


Explanation:

The empirical formula of a compound shows the simplest ratio of atoms present in the compound. To determine the empirical formula, we need to find the moles of each element.

First, we calculate the moles of aluminum using its molar mass of 26.98 g/mol:

Moles of aluminum = 10.0 g / 26.98 g/mol = 0.370 mol

Next, we calculate the moles of chlorine using its molar mass of 35.45 g/mol:

Moles of chlorine = 39.4 g / 35.45 g/mol = 1.11 mol

To find the simplest ratio, we divide the moles of each element by the smallest number of moles. In this case, the smallest number of moles is 0.370 mol:

Aluminum: 0.370 mol / 0.370 mol = 1

Chlorine: 1.11 mol / 0.370 mol = 3

Therefore, the empirical formula of the compound is AlCl3.


Learn more about Empirical formula here:

https://brainly.com/question/32125056


Thank you for reading the article What is the empirical formula of a compound that contains 10 0 g aluminum and 39 4 g chlorine Select the correct answer below A. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany

Other Questions