Thank you for visiting From the following balanced equation tex 2H 2 g O 2 g rightarrow 2H 2O g tex How many grams of tex H 2O tex. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
49.9 grams of H[tex]_{2}[/tex]O can be from 5.58 grams of H[tex]_{2}[/tex] from the given balanced dequation. Option A) 49.9 g is the correct answer.
To determine the amount of H[tex]_{2}[/tex]O that can be formed from 5.58 g of H[tex]_{2}[/tex], we need to use the balanced equation and stoichiometry.
From the balanced equation 2H[tex]_{2}[/tex](g) + O[tex]_{2}[/tex](g) → 2H[tex]_{2}[/tex]O(g), we can see that for every 2 moles of H[tex]_{2}[/tex], 2 moles of H[tex]_{2}[/tex]O are produced.
To calculate the number of moles of H[tex]_{2}[/tex] in 5.58 g, we divide the mass by the molar mass of H[tex]_{2}[/tex], which is 2 g/mol. Therefore, 5.58 g H[tex]_{2}[/tex] corresponds to 5.58 g / 2 g/mol = 2.79 mol H[tex]_{2}[/tex].
Since the mole ratio between H[tex]_{2}[/tex] and H[tex]_{2}[/tex]O is 1:1, the number of moles of H[tex]_{2}[/tex]O formed will also be 2.79 mol.
To convert the moles of H[tex]_{2}[/tex]O to grams, we multiply the number of moles by the molar mass of H[tex]_{2}[/tex]O, which is approximately 18 g/mol. Thus, the mass of H[tex]_{2}[/tex]O formed is 2.79 mol × 18 g/mol = 50.22 g.
Therefore, the correct answer is Option A) 49.9 g.
You can learn more about balanced dequation at
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