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Answer :
Answer:
The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.
Explanation:
Given;
the position of center of the target, xâ‚€ = 60 m
initial velocity of the bullet, u = 240 m/s
The time the bullet strikes the center of the large target is calculated as;
[tex]t = \frac{x_o}{u} =\frac{60}{240} = 0.25 \ s[/tex]
The distance from the center of the target to the point where the bullet strikes the target is calculated as;
x = vt + ¹/â‚‚gt²
where;
v is the final velocity of the bullet when it strikes the target = 0
x = 0 + ¹/â‚‚(9.8)(0.25²)
x = 0.31 m
Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.
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