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2. Calculate the molarity of each solution.

(a) 33.2 g of KCl in 0.895 L of solution

(b) 61.3 g of Câ‚‚Hâ‚‚O in 3.4 L of solution

(c) 38.2 mg of KI in 112 mL of solution

Answer :

The molarity of the KCl solution is 0.497 M. The molarity of the Câ‚‚Hâ‚‚O solution is 0.321 M. The molarity of the KI solution is 0.0021 M.

(a)

Mass of KCl = 33.2 g

The volume of solution = 0.895 L

the number of moles present in KCl is:

Molar mass of KCl = 39.10 g/mol + 35.45 g/mol

KCl molar mass = 74.55 g/mol

Number of moles of KCl = mass of KCl / molar mass of KCl

Number of moles of KCl = 33.2 g / 74.55 g/mol = 0.445 mol

The molarity of KCl is:

Molarity = number of moles of solute / total volume of solution

Molarity = 0.445 mol / 0.895 L

Molarity = 0.497 M

Therefore, we can infer that the molarity of the KCl solution is 0.497 M.

(b)

Mass of Câ‚‚Hâ‚‚O = 61.3 g

The volume of the solution = 3.4 L

Molar mass of Câ‚‚Hâ‚‚O solution = 2(12.01 g/mol) + 2(1.01 g/mol) + 16.00 g/mol

Molar mass of Câ‚‚Hâ‚‚O solution = 56.03 g/mol

Total Number of moles of Câ‚‚Hâ‚‚O = mass of Câ‚‚Hâ‚‚O / molar mass of Câ‚‚Hâ‚‚O

Total Number of moles of Câ‚‚Hâ‚‚O = 61.3 g / 56.03 g/mol = 1.094 mol

The molarity of the solution is:

Molarity = number of moles of solute/volume of solution in liters

Molarity = 1.094 mol / 3.4 L = 0.321 M

The molarity of the Câ‚‚Hâ‚‚O solution is 0.321 M.

(c)

Mass of KI = 38.2 mg

The volume of the solution = 112 mL

Molar mass of KI = 39.10 g/mol + 126.90 g/mol = 166.00 g/mol

Total number of moles of KI = mass of KI / molar mass of KI

Total number of moles of KI = 38.2 mg / 166.00 g/mol = 0.00230 mol

Here we need to convert the milliliters to liters.

Volume of solution = 112 mL ÷ 100 = 0.112 L

Now, we can calculate the molarity:

Molarity = number of moles of solute/volume of solution in liters

Molarity = 0.000230 mol / 0.112 L = 0.0021 M

The molarity of the KI solution is 0.0021 M.

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