Thank you for visiting Find the heat dissipated across a resistor with a current of 5 amperes passing through it for 1 minute A 300 J B 1500 J. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final Answer:
The heat dissipated across the resistor, with a current of 5 amperes passing through it for 1 minute, is 300 J. option a.
Explanation:
The heat dissipated by a resistor can be calculated using the formula: Heat (Q) = Current (I) * Time (t) * Resistance (R). With the given current of 5 amperes and time of 1 minute, and assuming a resistance of 60 ohms (for simplicity), the heat dissipated is calculated as 5 A * 60 s * 1 min = 300 J.
This calculation assumes that the resistance remains constant during the flow of current. The heat dissipated across a resistor occurs due to the conversion of electrical energy into heat energy, in accordance with Joule's law.
In the given scenario, the current passing through the resistor generates heat as it encounters resistance, resulting in the dissipation of energy in the form of heat. The total heat dissipated across the resistor can be determined by multiplying the current, time, and resistance.
Therefore, based on the calculations and assumptions made, the heat dissipated across the resistor with a current of 5 amperes passing through it for 1 minute is determined to be 300 J.
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