College

Thank you for visiting What is the molarity of a solution made by dissolving 39 4 g of lithium chloride in enough water to make 1 59 L of. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

What is the molarity of a solution made by dissolving 39.4 g of lithium chloride in enough water to make 1.59 L of solution?

[tex]
\[
\begin{array}{c}
\text{Molar mass of } LiCl: 42.39 \, \text{g/mol} \\
\text{Molarity} \, \left[\frac{\text{mol}}{L}\right]
\end{array}
\]
[/tex]

Answer :

To determine the molarity of the solution, we follow these steps:

1. Calculate the number of moles of lithium chloride ([tex]$\text{LiCl}$[/tex]) using the formula:
[tex]$$
n = \frac{m}{M}
$$[/tex]
where
- [tex]$m = 39.4\,\text{g}$[/tex] is the mass of [tex]$\text{LiCl}$[/tex],
- [tex]$M = 42.39\,\text{g/mol}$[/tex] is the molar mass of [tex]$\text{LiCl}$[/tex].

Thus,
[tex]$$
n = \frac{39.4\,\text{g}}{42.39\,\text{g/mol}} \approx 0.92946\,\text{mol}.
$$[/tex]

2. Calculate the molarity ([tex]$C$[/tex]) using the definition of molarity:
[tex]$$
C = \frac{n}{V}
$$[/tex]
where [tex]$V = 1.59\,\text{L}$[/tex] is the volume of the solution.

Therefore,
[tex]$$
C = \frac{0.92946\,\text{mol}}{1.59\,\text{L}} \approx 0.58457\,\frac{\text{mol}}{\text{L}}.
$$[/tex]

Rounded appropriately, the molarity of the solution is approximately [tex]$0.5846\,\text{M}$[/tex].

Thank you for reading the article What is the molarity of a solution made by dissolving 39 4 g of lithium chloride in enough water to make 1 59 L of. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany