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Answer :
Answer:
[tex]F=7.96*10^{-11}N[/tex]
Explanation:
According to Coulomb's law, the magnitude of the electric force between two equals charges (q) is given by:
[tex]F=\frac{kq^2}{d^2}[/tex]
Here k is the coulomb constant and d is the distance between the charges. For two electrons we have:
[tex]F=\frac{ke^2}{d^2}\\F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-1.6*10^{-19}C)^2}{(1.7*10^{-9}m)^2}\\F=7.96*10^{-11}N[/tex]
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