Thank you for visiting A 30 offset has been fabricated in a length of 3 4 inch RMC to clear an obstruction Determine the distance from the end of. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final Answer
The distance from the end of the 30° offset 3/4-inch RMC conduit to Mark 1 is approximately 15/16 inches.
Explanation:
To determine the distance from the end of the conduit to Mark 1, we need to consider the geometry of the 30° offset. The offset creates a right-angled triangle, where the length of the conduit acts as the hypotenuse. The tangent of the angle (30°) in this triangle can be used to find the horizontal displacement.
Let's denote the distance from the end of the conduit to Mark 1 as 'd'. The tangent of 30° is calculated as the ratio of the opposite side to the adjacent side:
[tex]\[ \tan(30^\circ) = \frac{d}{\frac{3}{4}} \][/tex]
Solving for 'd', we get:
[tex]\[ d = \frac{3}{4} \times \tan(30^\circ) \][/tex]
Now, let's calculate this value:
[tex]\[ d = \frac{3}{4} \times 0.577 \][/tex]
[tex]\[ d \approx 0.433 \][/tex]
However, this only represents the horizontal displacement. To find the total distance from the end of the conduit to Mark 1, we need to account for the vertical component of the offset. Considering the 3/4-inch RMC conduit as the hypotenuse, we apply the Pythagorean theorem:
[tex]\[ \text{Total distance} = \sqrt{\left(\frac{3}{4}\right)^2 + (0.433)^2} \][/tex]
Calculating this:
[tex]\[ \text{Total distance} \approx \sqrt{0.5625 + 0.187489} \][/tex]
[tex]\[ \text{Total distance} \approx \sqrt{0.749989} \][/tex]
[tex]\[ \text{Total distance} \approx 0.866 \][/tex]
Rounded to the nearest eighth inch, the final answer is approximately 15/16 inches.
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Rewritten by : Jeany
