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Answer :
Final answer:
To freeze a tray of ice cubes, 13.4 kJ of heat must be removed from the water.
Explanation:
To freeze a tray of ice cubes, heat must be removed from the water. The amount of heat that needs to be removed can be calculated using the equation: q = m * ΔH, where q is the amount of heat, m is the mass of the water, and ΔH is the molar heat of fusion of water.
First, we need to convert the mass of the water to moles. The molar mass of water is approximately 18 g/mol, so 40.0 g of water is equal to 40.0 g/18 g/mol = 2.22 mol of water.
Next, we can calculate the amount of heat needed to freeze the water: q = 2.22 mol * 6.01 kJ/mol = 13.3 kJ.
Therefore, 13.4 kJ of heat must be removed to freeze the tray of ice cubes.
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