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The same rifle fires a bullet with mass 11.7 g at the same speed as before. For the same idealized model, find the ratio of the final kinetic energies of the bullet and rifle.

Answer :

The final kinetic energy of the bullet is much smaller than that of the rifle, with a ratio of approximately 0.0029.

The kinetic energy of an object is given by the formula [tex]KE = (1/2)mv^2[/tex], where m is the mass of the object and v is its velocity. Since the rifle and bullet are fired at the same speed as before, the ratio of their final kinetic energies will depend only on their masses.

Let the mass of the rifle be M and the mass of the bullet be m. The ratio of the final kinetic energies of the bullet and rifle is given by:

[tex]KE_bullet/KE_rifle = (1/2)mv^2 / (1/2)Mv^2[/tex]

Simplifying this expression, we get:

[tex]KE_bullet/KE_rifle = m/M[/tex]

Substituting the given values, we get:

m = 11.7 g = 0.0117 kg

M = 4.0 kg

Therefore, the ratio of the final kinetic energies of the bullet and rifle is:

[tex]KE_bullet/KE_rifle[/tex] = m/M = 0.0117 kg / 4.0 kg = 0.002925

Thus, the final kinetic energy of the bullet is much smaller than that of the rifle, with a ratio of approximately 0.0029. This is because the bullet has a much smaller mass than the rifle, even though both were fired at the same speed.

To know more about kinetic energy refer to-

https://brainly.com/question/26472013

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