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Answer :
Final answer:
The pressure of the pure oxygen in the gas mixture is found by subtracting the vapor pressure of gaseous water from the total pressure, which equals 736.2 Torr. Therefore the correct option is b.
Explanation:
The question is about calculating the partial pressure of pure oxygen in a mixture of oxygen and gaseous water (steam) where the total pressure is known. According to Dalton's Law of Partial Pressures, the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of individual gases. Therefore, if the total pressure of the gas mixture in the tube is 760 Torr and the partial pressure of gaseous water (steam) is 23.8 Torr, the pressure of the pure oxygen can be found by subtracting the partial pressure of the water vapor from the total pressure.
To find the pressure of the pure oxygen gas we subtract the vapor pressure of the water from the total pressure:
Pressure of pure oxygen = Total pressure - Pressure of gaseous water
Pressure of pure oxygen = 760 Torr - 23.8 Torr = 736.2 Torr
The correct answer to the question is b. 736 Torr, indicating the pressure of the pure oxygen.
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Rewritten by : Jeany
