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What is the angular speed of (a) the second hand, (b) the minute hand, and (c) the hour hand of a smoothly running analog watch? Provide your answers in radians per second.

I calculated (a) to be [tex]\frac{2\pi}{60}[/tex], but I got (b) and (c) wrong. I thought a full revolution for the minute hand would be [tex]60 \, \text{sec/min} \times 60 \, \text{min/hour} = 3600 \, \text{sec}[/tex], but when using [tex]\frac{2\pi}{3600}[/tex], the answer is incorrect, and the same for the hour hand ([tex]\frac{2\pi}{21600}[/tex]). Please help!

Answer :

(a) Second hand: [tex]\( \frac{2\pi}{60} \)[/tex] rad/s. (b) Minute hand: [tex]\( \frac{2\pi}{3600} \)[/tex] rad/s. (c) Hour hand: [tex]\( \frac{2\pi}{43200} \)[/tex] rad/s.

The angular speed of each hand on a smoothly running analog watch depends on the timekeeping mechanism of the watch and the length of the hands.

(a) The second hand completes one full rotation (360 degrees) every 60 seconds. To find its angular speed in radians per second, we need to convert revolutions per minute to radians per second. Since there are [tex]\(2\pi\)[/tex] radians in one revolution, the angular speed of the second hand would be:

[tex]\[\text{Angular speed of second hand} = \frac{2\pi}{60} \text{ radians/second}\][/tex]

(b) The minute hand completes one full rotation every 60 minutes. Similar to the second hand, we can find its angular speed in radians per second:

[tex]\[\text{Angular speed of minute hand} = \frac{2\pi}{3600} \text{ radians/second}\][/tex]

(c) The hour hand completes one full rotation every 12 hours. So, its angular speed in radians per second would be:

[tex]\[\text{Angular speed of hour hand} = \frac{2\pi}{43200} \text{ radians/second}\][/tex]

These calculations assume that the watch has perfect timekeeping and the hands move continuously without any interruption .

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