Thank you for visiting When 95 0 g of an unknown metal is submerged in water in a graduated cylinder the water level rises from 38 2 mL to. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The density of the unknown metal is approximately 8.41 g/mL.
How to calculate the density
Volume of the metal = Final volume of water - Initial volume of water
= 49.5 mL - 38.2 mL
= 11.3 mL
Next, we need to convert the volume from milliliters (mL) to grams (g) because the mass is given in grams.
1 mL of water is equal to 1 gram, so:
Volume of the metal = 11.3 mL * 1 g/mL
= 11.3 g
Now we can calculate the density of the metal:
Density = Mass / Volume
= 95.0 g / 11.3 g
≈ 8.41 g/mL
Therefore, the density of the unknown metal is approximately 8.41 g/mL.
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