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Solve the equation using any method.

[tex] x^2 - 3x - 8 = 0 [/tex]

A. \{1.70, -4.70\}

B. \{1.70, 4.70\}

C. \{-1.70, -4.70\}

D. \{-1.70, 4.70\}

Answer :

We want to solve the quadratic equation

[tex]$$
x^2 - 3x - 8 = 0.
$$[/tex]

A standard method for solving quadratic equations is to use the quadratic formula. For an equation of the form

[tex]$$
ax^2 + bx + c = 0,
$$[/tex]

the solutions are given by

[tex]$$
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
$$[/tex]

In our equation, we have [tex]$a = 1$[/tex], [tex]$b = -3$[/tex], and [tex]$c = -8$[/tex]. Plugging these values into the quadratic formula gives:

[tex]$$
x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(1)(-8)}}{2 \cdot 1}.
$$[/tex]

First, compute the discriminant (the expression under the square root):

[tex]$$
\Delta = (-3)^2 - 4(1)(-8) = 9 + 32 = 41.
$$[/tex]

Thus, the formula becomes:

[tex]$$
x = \frac{3 \pm \sqrt{41}}{2}.
$$[/tex]

Now, to find approximate values, we evaluate [tex]$\sqrt{41}$[/tex]. We have:

[tex]$$
\sqrt{41} \approx 6.40.
$$[/tex]

Substitute this approximate value back into the solution:

1. For the solution with the minus sign:

[tex]$$
x \approx \frac{3 - 6.40}{2} = \frac{-3.40}{2} \approx -1.70.
$$[/tex]

2. For the solution with the plus sign:

[tex]$$
x \approx \frac{3 + 6.40}{2} = \frac{9.40}{2} \approx 4.70.
$$[/tex]

Thus, the solutions to the equation are approximately

[tex]$$
x \approx -1.70 \quad \text{and} \quad x \approx 4.70.
$$[/tex]

So, the answer is

[tex]$$
\{-1.70,\, 4.70\}.
$$[/tex]

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Rewritten by : Jeany