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A volume of helium occupies 11.71 L at a pressure of 99.8 kPa. What is the new volume if the pressure drops to 87.4 kPa?

Answer :

Final answer:

Using Boyle's Law, which establishes the inverse relationship between pressure and volume for a gas, we calculate that the new volume of helium when the pressure drops from 99.8 kPa to 87.4 kPa is approximately 13.33 liters.

Explanation:

To find the new volume when the pressure drops, we can use Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship, provided temperature and number of moles remain constant. The formula for Boyle's Law is P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

In this case:

  • P1 = 99.8 kPa
  • V1 = 11.71 L
  • P2 = 87.4 kPa
  • V2 = ?

Solving for V2, we have:

V2 = P1 × V1 / P2

V2 = (99.8 kPa × 11.71 L) / 87.4 kPa

V2 = 13.33 L (rounded to two decimal places)

So, the new volume if the pressure drops to 87.4 kPa is approximately 13.33 liters.

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