Thank you for visiting Use this information to answer the next two questions A 0 32 kg ball is thrown with a speed of 11 5 m s 18. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Given:
m = 0.32 kg
v = 11.5 m/s
To find:
1) Kinetic energy = ?
2) Work needed to stop the ball = ?
Formula used:
1) Kinetic energy = [tex] \frac{1}{2} m v^{2} [/tex]
2) Work = kinetic energy
Solution:
1)
Kinetic energy is given by,
Kinetic energy = [tex] \frac{1}{2} m v^{2} [/tex]
K.E. = [tex] \frac{1}{2} 0.32 \times 11.5 \times 11.5 [/tex]
K.E. = 21.16 Joule
Thus, option (d) is the correct answer.
2)
Work needed to stop the ball is same as the kinetic energy because energy is the capacity to do work. Since, work is opposing the movement of the ball. Thus, Work = - Kinetic energy
Work = -21.16 Joule
Thank you for reading the article Use this information to answer the next two questions A 0 32 kg ball is thrown with a speed of 11 5 m s 18. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
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Rewritten by : Jeany
