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Given the function [tex]f(x) = 4|x - 5| + 3[/tex], for what values of [tex]x[/tex] is [tex]f(x) = 15[/tex]?

A. [tex]x = 2, x = 8[/tex]
B. [tex]x = 1.5, x = 8[/tex]
C. [tex]x = 2, x = 7.5[/tex]
D. [tex]x = 0.5, x = 7.5[/tex]

Answer :

To solve the equation
[tex]$$
4|x-5| + 3 = 15,
$$[/tex]
follow these steps:

1. Subtract 3 from both sides:
This gives:
[tex]$$
4|x-5| = 15 - 3 = 12.
$$[/tex]

2. Divide both sides by 4:
Dividing by 4, we obtain:
[tex]$$
|x-5| = \frac{12}{4} = 3.
$$[/tex]

3. Solve the absolute value equation:
The equation
[tex]$$
|x-5| = 3
$$[/tex]
means that the expression inside the absolute value can be either [tex]$3$[/tex] or [tex]$-3$[/tex]. This leads to two cases:

- Case 1:
[tex]$$
x - 5 = 3 \quad \Longrightarrow \quad x = 5 + 3 = 8.
$$[/tex]

- Case 2:
[tex]$$
x - 5 = -3 \quad \Longrightarrow \quad x = 5 - 3 = 2.
$$[/tex]

4. Conclusion:
The solutions to the equation are:
[tex]$$
x = 2 \quad \text{and} \quad x = 8.
$$[/tex]

Thus, the values of [tex]$x$[/tex] for which [tex]$f(x)=15$[/tex] are [tex]$x=2$[/tex] and [tex]$x=8$[/tex].

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Rewritten by : Jeany