Answer :

Approximately 995,100 joules of heat energy are required to warm 1.70 kg of sand from 30.0°C to 100.0°C.

To calculate the heat required to warm the sand, we can use the formula:
Q = mcΔT
Where:
Q is the heat energy (in joules),
m is the mass of the sand (1.70 kg),
c is the specific heat capacity of sand (0.83 J/g°C),
ΔT is the change in temperature (final temperature - initial temperature).
First, we need to convert the mass from kilograms to grams: 1.70 kg = 1700 g.
Next, let's calculate the change in temperature: ΔT = 100.0°C - 30.0°C = 70.0°C.
Now we can substitute the values into the formula:
Q = (1700 g)(0.83 J/g°C)(70.0°C)
Q = 995,100 J

Learn more about heat energy here,
https://brainly.com/question/29210982

#SPJ11

Thank you for reading the article How much heat is required to warm 1 70 kg of sand from 30 0 C to 100 0 C. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany