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A 30 g bullet is fired from a 1.6 kg rifle at a target. If the muzzle velocity of the bullet is 360 m/s, what is the recoil velocity of the rifle?

Answer :

The recoil velocity of the rifle is approximately 0.675 m/s in the opposite direction of the fired bullet.

According to the principle of conservation of momentum, the total momentum of a system before and after an event remains constant, provided that no external forces act on the system.

In this scenario, the rifle and bullet form a system, and their total momentum before firing is zero since they are initially at rest. When the bullet is fired, it gains momentum in one direction, which means that the rifle must gain an equal and opposite momentum in the other direction to conserve momentum.

We can use the following equation to determine the recoil velocity of the rifle (váµ£):

mᵢvᵢ = mᵣvᵣ + mbvᵦ

where mᵢ and vᵢ are the mass and initial velocity of the rifle, mᵣ and vᵣ are the mass and recoil velocity of the rifle, mb and vᵦ are the mass and velocity of the bullet.

Substituting the given values, we get:

(1.6 kg)(0 m/s) = máµ£váµ£ + (0.03 kg)(360 m/s)

Simplifying the equation, we get:

máµ£váµ£ = -(0.03 kg)(360 m/s)

váµ£ = -(0.03 kg)(360 m/s)/(1.6 kg)

váµ£ = -0.675 m/s

For more question on recoil velocity visit:

https://brainly.com/question/29180521

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