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A rifle that shoots bullets at 450 m/s is aimed at a target 49.2 m away. If the center of the target is level with the rifle, how high above the target must the rifle barrel be pointed so that the bullet hits dead center? (Neglect air resistance.)

Answer :

The rifle barrel must be pointed approximately 0.0581 meters or 5.81 centimeters above the target to hit dead center.

To determine how high above the target the rifle barrel must be pointed, we can use the principles of projectile motion. We need to find the vertical displacement or the height above the target that the bullet must travel.

Let's break down the problem and solve it step by step:

First, we can consider the horizontal motion of the bullet. Since there is no acceleration horizontally, the time it takes for the bullet to travel 49.2 m horizontally is given by the formula:

time = distance / velocity

time = 49.2 m / 450 m/s

time ≈ 0.1093 s

Now, let's consider the vertical motion of the bullet. We can use the formula for vertical displacement in projectile motion:

displacement = initial vertical velocity * time + (1/2) * acceleration * [tex]time^2[/tex]

Since the bullet starts at the same height as the target and we want it to hit dead center, the initial vertical velocity is zero.

displacement = 0 * time + (1/2) * acceleration *[tex]time^2[/tex]

The only force acting on the bullet vertically is gravity, which causes it to accelerate downward. The acceleration due to gravity is approximately 9.8 m/[tex]s^2[/tex].

[tex]displacement = (1/2) * 9.8 m/s^2 * (0.1093 s)^2[/tex]

displacement ≈ 0.0581 m

To know more about projectile motion refer here

https://brainly.com/question/12860905#

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