Thank you for visiting Select the correct answer The atomic mass of potassium is 39 1 What is the mass of tex 6 02 times 10 23 tex atoms. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To find the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium, we need to relate the atomic mass to the concept of a mole. The atomic mass of potassium is given as 39.1. This value represents the mass of one mole of potassium atoms, which corresponds to Avogadro's number, [tex]\(6.02 \times 10^{23}\)[/tex] atoms.
Here's the step-by-step solution:
1. Understand the Concept:
- The atomic mass (in grams) of an element is the mass of one mole of its atoms. For potassium, this is 39.1 grams.
2. Relate to Avogadro's Number:
- Avogadro's number, [tex]\(6.02 \times 10^{23}\)[/tex], is the number of atoms in one mole. Therefore, 39.1 grams of potassium is the mass of [tex]\(6.02 \times 10^{23}\)[/tex] potassium atoms.
3. Conclusion:
- Since the atomic mass provided is 39.1 g for [tex]\(6.02 \times 10^{23}\)[/tex] atoms, that's the mass we're asked to find.
Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams. So, the correct answer is:
B. [tex]\(39.1 \, \text{g}\)[/tex]
Here's the step-by-step solution:
1. Understand the Concept:
- The atomic mass (in grams) of an element is the mass of one mole of its atoms. For potassium, this is 39.1 grams.
2. Relate to Avogadro's Number:
- Avogadro's number, [tex]\(6.02 \times 10^{23}\)[/tex], is the number of atoms in one mole. Therefore, 39.1 grams of potassium is the mass of [tex]\(6.02 \times 10^{23}\)[/tex] potassium atoms.
3. Conclusion:
- Since the atomic mass provided is 39.1 g for [tex]\(6.02 \times 10^{23}\)[/tex] atoms, that's the mass we're asked to find.
Therefore, the mass of [tex]\(6.02 \times 10^{23}\)[/tex] atoms of potassium is 39.1 grams. So, the correct answer is:
B. [tex]\(39.1 \, \text{g}\)[/tex]
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