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Answer :
Calculated using the Ideal Gas Law. We used the formula PV = nRT and rearranged it to V = nRT / P to find the volume. After substituting the given values and solving, we obtained the final answer.
Solution
In order to solve this, we will use the Ideal Gas Law:
PV = nRT
Where:
- P is the pressure (1.70 atm)
- V is the volume (in liters, which we need to find)
- n is the number of moles (4.00 moles)
- R is the ideal gas constant (0.0821 L·atm/K·mol)
- T is the temperature in Kelvin (16°C + 273.15 = 289.15 K)
Rearrange the Ideal Gas Law to solve for volume (V):
V = nRT / P
Plug in the values:
V = (4.00 moles) × (0.0821 L·atm/K·mol) × (289.15 K) / 1.70 atm
Calculate:
V = 55.9233 / 1.70
V ≈ 32.90 L
Therefore, the volume of 4.00 moles of methane gas at 16°C and 1.70 atm is approximately 32.90 L.
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