High School

Thank you for visiting What is the pOH of a solution with tex left text OH right 2 0 times 10 2 tex A 1 70 B 1 70. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

What is the pOH of a solution with [tex]\left[ \text{OH}^{-} \right] = 2.0 \times 10^{-2}[/tex]?

A. -1.70
B. 1.70
C. 3.01
D. 2.00

Answer :

To find the pOH of a solution given the hydroxide ion concentration [tex]\([OH^-] = 2.0 \times 10^{-2}\)[/tex], we can use the formula for pOH:

[tex]\[ \text{pOH} = -\log_{10}([OH^-]) \][/tex]

Let's calculate it step-by-step:

1. Identify the concentration of hydroxide ions:
[tex]\([OH^-] = 2.0 \times 10^{-2}\)[/tex].

2. Apply the formula:
[tex]\(\text{pOH} = -\log_{10}(2.0 \times 10^{-2})\)[/tex].

3. Calculate the logarithm:
When you compute [tex]\(-\log_{10}(2.0 \times 10^{-2})\)[/tex], you get approximately 1.70.

Thus, the pOH of the solution is approximately 1.70.

The correct answer is B. 1.70.

Thank you for reading the article What is the pOH of a solution with tex left text OH right 2 0 times 10 2 tex A 1 70 B 1 70. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany