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Answer :
Final answer:
The volume of 1.70 mol of liquid water at 20°C, given a density of 998 kg/m³, is approximately 30.7 mL.
Explanation:
To calculate the volume of 1.70 mol of liquid water at 20°C, where the density of water is 998 kg/m³, we first need to find the mass of water. We know from the molecular mass of water (H2O) is approximately 18.0 g/mol. Therefore, the mass (m) of 1.70 mol of water can be calculated as follows:
- m = n × M
- m = 1.70 mol × 18.0 g/mol
- m = 30.6 g
Since 1 kilogram is equal to 1000 grams, we convert mass from grams to kilograms:
- m = 30.6 g × (1 kg/1000 g)
- m = 0.0306 kg
Now, to find the volume (V), we use the definition of density (ρ), which is mass per unit volume: ρ = m/V. We rearrange this to find V:
- V = m/ρ
- V = 0.0306 kg / 998 kg/m³
- V ≈ 0.0000307 m³ or 30.7 mL
The volume of 1.70 mol of liquid water at 20°C is approximately 30.7 mL.
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