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Answer :
Final answer:
The de Broglie wavelength of the mosquito is approximately 2.89 x [tex]10^-28[/tex] meters.
Explanation:
The de Broglie wavelength of a particle can be calculated using the equation: λ = h / mv, where λ is the de Broglie wavelength, h is Planck's constant (6.63 x 10-34 J*s), m is the mass of the particle, and v is the velocity of the particle.
In this case, the mass of the mosquito is 1.70 mg, which is equal to 1.70 x 10-6 kg, and the velocity of the mosquito is 1.62 m/s.
Plugging these values into the equation, we have:
λ = (6.63 x 10-34 J*s) / (1.70 x 10-6 kg x 1.62 m/s)
λ = 2.89 x 10-28 m
Therefore, the de Broglie wavelength of the mosquito is approximately 2.89 x [tex]10^-28[/tex] meters.
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